Math, asked by anubingi2gmailcom, 1 year ago

Madhav, Munjal and Melkote together contributed to
buy a bike for 345000. Munjal paid one-third of the
total amount paid by Madhav and Melkote. Madhav
paid half of the total amount paid by Munjal and
Melkote. How much did Melkote pay for the bike?
(A) 712,750
(B) 317,250
(C) 318,750
(D) 19,250​

Answers

Answered by 23saurabhkumar
3

Answer:

Amount paid by Melkote, y = \frac{5x}{4} = 143750 Rs.

Step-by-step explanation:

In the question,

Total amount contributed by three of them together = 345000

Now,

Let us say that Amount contributed by Madhav = x

and,

Amount Contributed by Melkote = y

So,

Amount contributed by Munjal is,

=\frac{x+y}{3}

Also,

Amount paid by Madhav is,

=\frac{\frac{(x+y)}{3}+y}{2}\\=\frac{x+4y}{6}

So,

x=\frac{x+4y}{6}\\6x=x+4y\\5x=4y\\So,\\y=\frac{5x}{4}

Now,

Total amount = Madhav's + Munjal's + Melkote's

So,

345000=x+\frac{3x}{4}+\frac{5x}{4}\\So,\\3x=345000\\x=115000

So,

Amount paid by Melkote, y = \frac{5x}{4} = 143750 Rs.

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