madhav sold a toy car at a loss of 5 per cent. Had it been sold for RS. 30 more, he would have gain 10 per cent. Find its cost price.
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Step-by-step explanation:
Rs.200
Step-by-step explanation:
Let CP be x of toy
Now we are given that Raman sold a toy at a loss of 20%.
Loss = \frac{20}{100} x10020x
SP = CP -Loss
SP = x-\frac{20}{100}xSP=x−10020x
SP = \frac{80}{100}xSP=10080x
Now we are given that if Had he sold for rs 100 more, he would have made a profit of 30%
Profit = 30 \% \times x30%×x
Profit = \frac{30}{100} \times x10030×x
SP = CP+Profit
Sp = x+\frac{30}{100}xSp=x+10030x
Sp =\frac{130}{100}xSp=100130x
ATQ
\frac{130}{100}x-\frac{80}{100}x=100100130x−10080x=100
\frac{50}{100}x=10010050x=100
x=200x=200
Hence the cost price of toy is Rs.200
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2
Answer:
the cos of the toy is 200 ...
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