Question

madhav tries to focus the image of a box on the screen which is placed at distance of 60 cm in front of a spherical mirror keeping the mirror at a distance of 15cm from the box what type of mirrors is used., linear magnificent of image, distance between p and f., diagram​

Answer 1

Answer:

I also want the answer

Explanation:

this question is also in my holiday homework

Answer 2

Answer :

Given Data :

Image distance(v) = -60 cm

Object distance (u) = - 15 cm

Formula to be used =

Mirror Formula:

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

where f is the focal length of the lens.

Obtaining Results :

$\frac{1}{( - 60)} + \frac{1}{( - 15)} = \frac{1}{f} \\ \frac{ - 1}{60} - \frac{1}{15} = \frac{1}{f} \\ \frac{1}{f} = \frac{ - 1 - 4}{60} = \frac{ - 5}{60} \\ f = \frac{ - 60}{5} = - 12\: cm$

So, the focal length of the mirror is -12 cm, since it is negative, then the mirror is concave mirror.

Now,

$magnification \: = \frac{ - v}{u} = \frac{ - ( - 60)}{( - 15)} = - 4$

Hence, the magnification of the mirror is -4 .

The distance between pole (p) and focus(f) = focal length = -12 cm.

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