Math, asked by 9852841036, 1 year ago

Madhu and Meena can do a piece of work in 9 hours. Meena and Mamta can do it 12 hours and Madhu and Mamta can do it in 18 hours. in how many hours will they will finish the work together and separately?

Answers

Answered by amitnrw
2

Answer:

All together = 8 hrs

Madhu = 24 hrs

Meena = 14.4 hrs

Mamta = 72 hrs

Step-by-step explanation:

Madhu = A

Meena = B

Mamta = C

1/9 = 1/A + 1/B

1/12 = 1/B + 1/C

1/18 = 1/A + 1/C

Adding all

1/9 + 1/12 + 1/18  = 2 (1/A + 1/B + 1/C)

4 + 3 + 2 = 36*2 (1/A + 1/B + 1/C)

9/72 = (1/A + 1/B + 1/C)

1/8 = 1/A + 1/B + 1/C

So all together can do in 8 Hrs

1/C = 1/8 - 1/9 = 1/72 so C = 72 hrs

1/B = 1/8 - 1/18 = 5/72 so B = 72/5 = 14.4 Hrs

1/A = 1/8 - 1/12 = 1/24 so A = 24 Hrs

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9852841036: wrong answer
amitnrw: How
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