Question

Madhu bought a house for rs.13125000. if its value depreciates at the rate of 10%p.a what will be its sale prize after 3years​

Answer 1

Manu brought a house = 13125000

it value depreciates at the rate = 10%

time= 3 years

=p (1-r/100)^t

=13125000(1-10%/100)^3

=13125000 ×90/100×90/100 ×90/100

= 9568125 rupee

Answer 2

Answer:

$\huge\red{s}\pink{o}\blue{l}\orange{t}\green{u}\gray{i}\red{o}\blue{n} \:$

Price of a house (P) = ₹1,31,25,000

Rate of depreciation = 10% p.a

Time = 3 years

sale price after 3 years = P( 1 - r/10 ) n

$= 13125000(1 - \frac{10}{100} {)}^{3}$

$= 13125000 = ( \frac{100 - 10}{100} {)}^{3}$

$= 13125000 ( \frac{90}{100} {)}^{3}$

$= \frac{13125000 \times 90 \times 90 \times 90}{100 \times 100 \times 100}$

$= 13125 \times 9 \times 9 \times 9$

$= 13125 \times 729$

$= 9568125$

Step-by-step explanation:

i hope it helps you :)