Question

Madhu has 25 mangoes less than the mangoes that Ram and Hari together have
and Hari has thrice as many as Ram has. If there are altogether 95 mangoes, how
many has each of them?
​

Answer 1

Answer:

• Let the Ram Have n Mangoes.
• & as Hari has Thrice of Ram, then Hari has 3n Mangoes.

☯ According to the First Statement :

⇾ Madhu = (Ram + Hari) – 25

⇾ Madhu = (n + 3n) – 25

⇾ Madhu = 4n – 25

__________________

☯ Total Mangoes :

⇢ Madhu + Ram + Hari = Total

⇢ 4n – 25 + n + 3n = 95

⇢ 4n + n + 3n = 95 + 25

⇢ 8n = 120

• Dividing both term by 8

⇢ n = 15

━━━━━━━━━━━━━━━━━━━

☢ Each Having Mangoes :

⇴ Ram = n = 15

⇴ Hari = 3n = 3(15) = 45

⇴ Madhu = 4n – 25 = 4(15) – 25 = 35

∴ Ram, Hari and Madhu have 15, 45 and 35 mangoes respectively.

Answer 2

AnswEr :

Let Ram Have x Mangoes.

$:\implies\sf Hari=Thrice\:of\:Ram\\\\\\:\implies\sf Hari=3\times x\\\\\\:\implies\sf Hari=3x$

⠀

$:\implies\sf Madhu=25\:Less\:than\:(Ram+Hari)\\\\\\:\implies\sf Madhu=(x+3x)-25\\\\\\:\implies\sf Madhu=4x-25$

$\rule{90}{1}$

☯⠀$\underline{\textsf{Let's Head to the Question Now :}}$

$:\implies\sf Ram+Hari+Madhu=Total\\\\\\:\implies\sf x+3x+4x-25=95\\\\\\:\implies\sf 8x=120\\\\\\:\implies\sf x=\dfrac{120}{8}\\\\\\:\implies\sf x=15$

$\rule{180}{2}$

☯⠀$\underline{\textsf{Each Person Have :}}$

$\bullet\:\:\sf Ram=x=15\\\bullet\:\:\sf Hari=3x=45\\\bullet\:\:\sf Madhu=4x-25=35$