Math, asked by taranarani786, 11 hours ago

Madhu is four years older than Neha.Eight years ago,Madhu was three times Neha's age.find the ages of Madhu and Neha after three year
2649pls solve it

Answers

Answered by chauhanarshi88
0

Answer:

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Answered by RvChaudharY50
0

Given :- Madhu is four years older than Neha. Eight years ago,Madhu was three times Neha's age.

To Find :- The ages of Madhu and Neha after three years ?

Solution :-

Let us assume that, present age of neha is x years .

So,

→ Present age of madhu = (x + 4) years .

then,

→ 8 years ago neha age = (x - 8) years

→ 8 years ago madhu age = (x + 4) - 8 = (x - 4) years .

A/q,

→ (x - 4) = 3(x - 8)

→ x - 4 = 3x - 24

→ 3x - x = 24 - 4

→ 2x = 20

→ x = 10 years .

therefore,

→ Madhu age after three years = (x + 4) + 3 = (10 + 4) + 3 = 14 + 3 = 17 years .

Neha age after three years = x + 3 = 10 + 3 = 13 years .

Hence, ages of Madhu and Neha after three year is equal to 17 years and 13 years respectively.

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