Math, asked by darrW, 8 months ago

Madhu was collecting money from the class for picnic. She could collect 4 times more notes of ₹50 than ₹20. If the total amount collected is ₹1100. How many notes of each kind does she have?

Answers

Answered by Muheeth
5

Answer:

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Step-by-step

explanation:

Let us consider number of 20 rupee notes as X. And number of 50 rupee notes as Y

As Sharda has 5 times 20 rupee notes as many 50 rupee notes, so

5X=Y

And altogether sum is 900 rupees,

X number of notes of 20 rupees and Y number of notes of 50 rupees,

20X+50Y=900

But we've to find X and as 5X=Y,

Substituting Y in terms of X, we get the equation as:

20X+50(5X)=900

20X+250X=900

270X=900

X=3.33 which is not integer (number of notes) and hence we can conclude that the sum of Rupees 900 is incorrect…so if it would've been a hypothetical question, then answer of X is 3.33 and as Y is 5 times of X, we can see that Y is 16.66 number of notes (Again which is not possible as not integer)

Thus the number of 20 rupee notes is 3.33

And number of 50 rupee notes is 16.66.

And even if we cross verify, the sum comes to 900 by the equation 20X+50Y=900

Hope this helps

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Answered by hemakumar0116
0

Answer:

Total notes of ₹20 is 5 and Total notes of ₹50 is 20.

Step-by-step explanation:

Given that

  • Madhu was collecting money from the class for picnic.
  • She could collect 4 times more notes of ₹50 than ₹20.
  • The total amount collected is ₹1100.

To find,

  • How many notes of each kind does she have?

Explanation,

According the Question

We have,

  • Total amount collected = ₹1100
  • She collected 4 times more notes of ₹50 than ₹20.

Now,

Lets assume,

  • Total notes of ₹20 = x
  • Total notes of ₹50 = y

Now,

       Total amount collected = 1100

       20x + 50y = 1100 -------------------(1)

Lets assume it as equation --- (1)

and from question,

       4 times of notes of 20 = notes of 50

       4x = y -------------------(2)

Lets assume it as equation --- (2)

Now putting the value of equ. (2) in equ. (1)

So, we get

       20x + 50y = 1100 -------------------(1)

       20x + 50 × (4x) = 1100

       20x + 200x = 1100

       220x = 1100

       x = \frac{1100}{220}

       x = \frac{110}{22}

       x = 5

Now putting the value of x in equ. (2),

So, we get

       4x = y -------------------(2)

       4 × 5 = y

       20 = y

           or

       y = 20.

Answer: Total notes of ₹20 is 5 and Total notes of ₹50 is 20.

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