Physics, asked by deeptiaggarwal53, 9 months ago

madhurima Chatterjee Abhishek aur moderator mujhe ismein sirf distance bata do Baki Mera solve Ho Gaya ki 20 metre kaise aaya baki mera sara Ho Gaya

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Answered by Anonymous

Answer:

Initial speed of the three-wheeler, u = 36 km/h = 10 m/s

Final speed of the three-wheeler, v = 0 m/s

Time, t = 4 s Mass of the three-wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

∴ a = v - u / t = 0-10/4 = -2.5 m/s2

The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma = 465 × (–2.5)

= –1162.5 N

The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.

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