Math, asked by rehmath8823, 4 months ago

Madison invested $3,300 in an account paying an interest rate of 6.7% compounded daily. Assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 5 years?

Answers

Answered by lodhiyal16
3

Answer:

Step-by-step explanation:

Madison invested = $ 3300

Rate of interest = 6.7 %

Time = 5 years

amount =  Principal ( 1 + r /100 ) ^time

Amount = $3300 ( 1 + 6.7 /100 ) ^  5

Amount = $3300 ( 1 + 6.7/100 ) ^5

Amount = $3300 ( 106.7 /100)^5

Amount = $3300 (1.067 ) ^5

Amount = $3300 ( 1.382)

Amount = $4563.89

He will receive $4563 .89 in 5 years

Answered by alyssiamcdaniel9068
7

Answer:

Step-by-step explanation:

A=P(1+ nr

)

nt

Compound interest formula

P

=

3300

r

=

0.067

t

=

5

n

=

365

P=3300r=0.067t=5n=365

Given values

A

=

3300

(

1

+

0.067

365

)

365

(

5

)

A=3300(1+

365

0.067

)

365(5)

Plug in values

A

=

3300

(

1.0001835616

)

1825

A=3300(1.0001835616)

1825

Simplify

A

=

4613.06145057

A=4613.06145057

Use calculator

A

4610

A≈4610

Similar questions