Question

Maganbhai moves along the boundary of a square field of side 20m in 80s. What will be the magnitude of displacement of maganbhai at the end of 4min 40s from his initial position?​

Answer 1

Answer:

side of square = 20m Perimeter of square = 20 × 4 =80 square meter Time taken to complete 1 round = 80 s Thus, man 80m/80s = 1m/s. moving at a speed of Thus, distance covered in 4 min 40 s i.e. 4 × 60 + 40 s = 240 + 40 = 280 sec with the same speed = 280 m 280 m = 280/80 = 3.5 . Number of rounds completed to cover After making 3 revolutions, the displacement will become zero. And for the remaining 0.5 m the man will be at the opposite end diagonally from his starting point. So the magnitude of displacement is, S2 = 202 + 202 = 400 + 400 = 800 S = (800 )

Explanation:

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