Magine a 10% sucrose is separated from a 20% sucrose solution by a membrane impermeable to sucrose. How can equilibrium be reached in this situation
Answers
If a U tube is divided by a permeable membrane, filled on one arm with pure water and the other with a solution of sucrose, the molecules of sucrose will diffuse through the permeable membrane towards water because the diffusion pressure and concentration of sucrose molecules are higher on the right-hand than on the left- hand side and the water molecules will move in the opposite direction for its diffusion pressure or concentration is higher in the left portion than in the right.
Thus there will be a thorough mixing of both sucrose and water molecules in the two arms of the tube. An equilibrium is eventually established between the two arms of the tube when equal quantities of sucrose and water molecules are present on the two sides of the partition.
If the membrane is more rapidly penetrated by one of the two substances that substance will at first pass more quickly than the other but ultimately equalisation of the concentration and the pressure of the solutions in the two arms must result.
The case will be very different, however, when the partition, separating the two liquids is semipermeable, i.e., permeable only to the molecules of water while molecules of sucrose are quite unable to pass through it
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