Physics, asked by ineshdahiya, 1 year ago

magitude of position vector in 2-D is 4. its slope is 1/root 3 the position vector is

Answers

Answered by tejugana
11

Explanation:

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Answered by mdimtihaz
5

The position vector is: \vec r=2[\sqrt3\hat{i}+\hat{j}]

Explanation:

  • The Magnitude of the position vector is 4 and the slope is \frac{1}{\sqrt3}.
  • The Slope of a vector is tan\theta.
  • tan\theta=\frac{1}{\sqrt3}\\

           \theta=30^\circ

  • The position is denoted as, \vec r=rcos\theta\hat{i}+rsin\theta\hat{j}
  • \vec r=4cos30^\circ\hat{i}+4sin30^\circ\hat{j}
  • \vec r=4\frac{\sqrt3}{2}\hat{i}+4\frac{1}{2}\hat{j}
  • \vec r=2\sqrt3\hat{i}+2\hat{j}\\\vec r=2[\sqrt3\hat{i}+\hat{j}]

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