magnesium and oxygen combine in the ratio of 3 is to 2 by mass to form magnesium oxide what mass of Oxygen gas would be required to react completely with 24 grams of magnesium
Answers
Answered by
57
This problem can be solved according to Law of Chemical Combination -
As the amount of magnesium and oxygen are in ratio 3:2 .
So, amount of magnesium is 24 gm and let amount of oxygen be x.
=> 3:2
=> 24:x
3/2= 24/x
By cross multiplying ,we get
x= 16 gm
As the amount of magnesium and oxygen are in ratio 3:2 .
So, amount of magnesium is 24 gm and let amount of oxygen be x.
=> 3:2
=> 24:x
3/2= 24/x
By cross multiplying ,we get
x= 16 gm
panjaliagratha:
can u please give the ans in 2 marks type
Answered by
6
Answer:
16 g
Explanation:
The question can be solved through the Law of Conservation of mass.
As it is given in the question the mass of the Mg is in the ratio of 3:2 compared to the mass of . So,
3x+2x = Mg +
but 3x = 24g
=> x = 8g
then, the mass of is 2x which is 2 multiplied by 8 = 16g
Hope I helped you!
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