Question

Magnesium carbonate and hydrochloric acid react to produce salt, water and carbon dioxide.what is the volume of Co2 produced when 21g of magnesium carbonate reacts completely with excess hydrochloric acid?

Answer 1

Answer:

MgCO3+2HCl-------->MgCl2+CO2+H2O

Answer 2

Given:

The mass of Magnesium Carbonate = 21 gm

To Find:

The volume of CO2 produced when 21 gm of magnesium carbonate reacts completely with excess hydrochloric acid.

Calculation:

- The chemical reaction is given as:

MgCO3 + 2 HCl → MgCl2 + H2O + CO2

⇒ The moles of CO2 produced from 1 mole of MgCO3 = 1 mole

⇒ The volume of CO2 produced from 84 gm MgCO3 = 22.4 L

⇒ The volume of CO2 produced from 21 gm MgCO3 = (22.4/84) × 21 = 5.6 L

- So, 5.6 Litre of CO2 is produced when 21 gm of magnesium carbonate reacts completely with excess hydrochloric acid.