Question

Magnesium hydroxide (Mg(OH)2), as "Milk of Magnesia" can be used to neutralize excess stomach acid, represented by HCl(aq):
Mg(OH)2(s) + 2HCl(aq)  MgCl2(aq) + 2H2O(l)
When 5.00 g of HCl are combined with an excess of Mg(OH)2, what mass of MgCl2 can be produced?

Answer 1

$\huge \underline{ \boxed{ \green{ \sf{Given}}}}$

• When 5.00 g of HCl are combîned with an excéss of Mg(OH)₂.

$\huge\underline{ \boxed{ \red{ \sf{Find \: Out:−}}}}$

• What mass of MgCl₂ can be produced?

$\huge{ \underline{ \orange{ \sf{Solution :-}}}}$

• Magnesium hydroxide Mg(OH)₂, as "Milk of Magnesia" can be used to neutralize excess stomach acid, represented by HCl(aq) :

$\bullet\:{\underline{\red{ \sf{Mg(OH)_2(s) + 2HCl\: (aq) \rightarrow\: MgCl_2\:(aq) + 2H_2O(l)}}}}$

$\huge{ \frak{☣ Moles \: of \: HCl :-}}$

We have :

Mass = 5.00 g

Molar Mass = 36.5 g/mol

$➙ \red{ \boxed{\sf{Moles =\: \dfrac{Given\: Mass}{Molar\: Mass}}}}$

$➙ \sf{ \red{ Mole}}= \sf{ \red}\dfrac{5.00}{36.5}$

$➙ {\small{\bold{\pink{\underline{Mole =\: 0.137\: Moles}}}}}$

☣ Mass of MgCl₂ can be produced :-

$\huge{ \underline{ \sf{we \: have : }}}$

• Number of Moles = 0.0685 Mole
• Mass = 58 g/mol

$\begin{gathered}\red{ \boxed{\sf{Mass =\: Number\: of\: Moles \times Molar\: Mass}}}\\\end{gathered}$

$➔ \sf Mass =\: 0.0685 \times 58Mass$

• Henceforth, the mass of MgCl₂ can be produced is 3.973 g.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Magnesium hydroxide :-

• Magnesium hydroxide is the inorganic compound with the chemical formula Mg(OH)₂.

• It occurs in nature as the mineral brucite. It is a white solid with low solubility in water.

• Molar Mass :

• Molar mass is the mass of a given substance divided by the amount of that substance, measured in g/mol.

• The units of molar mass are grams per mole, abbreviated as g/mol.

Answer 2

Explanation:

it is

g/mol

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