Question

Magnesium reacts with an element x to form an ionic compound . If the ground state electronic configuration is 1s2 2s2 2p3 the simplest formula fir this compund is

Answer 1

Answer: [tex]Mg_3N_2[/tex].

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

$Mg:12:1s^22s^22p^63s^2$

$Mg^{2+}:10:1s^22s^22p^6$

$N:7:1s^22s^22p^3$

$N^{3-}:10:1s^22s^22p^6$

Here magnesium is having an oxidation state of +2 called as $Mg^{2+}$ cation and nitrogen $N^{3-}$ is an anion with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Mg_3N_2$.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

Answer 2

Answer:see the attachment

Good luck

Explanation: