Question

magnesium ribbon is burnt in the air to give a white compound 'X' accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitracon, it continues to burn and forme a compound V​

Answer 1

QUESTION:

magnesium ribbon is burnt in the air to give a white compound 'X' accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitracon, it continues to burn and forme a compound V

SOLUTION:

Magnesium ribbon burns in oxygen(O 2 ) to form magnesium oxide (MgO).

$\\ \\ 2Mg+O2→2MgO$

Therefore X is MgO.

Therefore X is MgO.Burning magnesium ribbon reacts with nitrogen(N2 ) to form magnesium nitride(Mg 3 N2)

$\\ \\ 3Mg+N2→Mg3N2$

$\\ \\ \\ Therefore, Y is Mg3N2 \\ \\ </em></p><p></p><p></p><p><em>[tex] \\ \\ \\ Therefore, Y is Mg3N2 \\ \\ Hence \: the \: correct \: option \: is \: C.</em></p><p></p><p><em>[tex] \\ \\ \\ Therefore, Y is Mg3N2 \\ \\ Hence \: the \: correct \: option \: is \: C.$

Answer 2

Answer:

then

\: \: \: \: (1) \: tan \theta \: = \: \sqrt{ {r}^{2} - 1}(1)tanθ=

r

2

−1

\: \: \: \: (2) \: cos \theta \: = \: r(2)cosθ=r

\: \: \: \: (3) \:sin \theta \: + cos \theta \: = \: \dfrac{ \sqrt{1 + {r}^{2} } }{r}(3)sinθ+cosθ=

r

1+r

2

\: \: \: \: (4) \: cot \theta \: = \: \sqrt{1 - {r}^{2}}(4)cotθ=

1−r

2