Magnetic field at centre of a current carrying circular
coil of radius R is 8 times the value of magnetic field
on its axis at a distance x from the centre. The value
of x is:
R/√3
√2R
R√3
√3R/2
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Explanation:
B=
2R
μ
∘
Ni
....(i)
Given magnetic field B
′
at distance Z from center is
8
B
B
′
=
8
1
2R
μ
∘
Ni
....(ii)
From above concept B
′
=
2((R
2
+Z
2
)
2
3
μ
∘
NiR
2
....(iv)
From equation (ii) and (iv)
2((R
2
+Z
2
)
2
3
μ
∘
NiR
2
=
8
1
2R
μ
∘
Ni
8R
3
=(R
2
+Z
2
)
2
3
taking cube root on both sides
2R=
R
2
+Z
2
⇒Z=
3
R
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