Physics, asked by shivangi2729, 11 months ago

Magnetic field at point O is

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Answered by aristocles
28

Answer:

Magnetic field at point O due to given loop is

B = \frac{5\mu_o i}{48 R}

Explanation:

As we know that the magnetic field due to current carrying loop is given as

B = \frac{\mu_o i}{2R}

now for given system we have two quarter circle loop of different radius and one semi circle loop of different radius

So here we have

B = \frac{\mu_o i}{8(2R)} + \frac{\mu_o i}{8(R)} - \frac{\mu_o i}{4(3R)}

B = \frac{\mu_o i}{4R} (\frac{1}{4} + \frac{1}{2} - \frac{1}{3})

B = \frac{\mu_o i}{4R}(\frac{3 + 6 - 4}{12})

B = \frac{5\mu_o i}{48 R}

#Learn

Topic : Magnetic field

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Answered by kirtiroy0103
5

Answer:

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