Question

magnetic field change at the rate of 0.4T/sec in a square coil of side 4cm .kept perpendicular to the field .if the resistance of the coil is 2*10_3ohm then induced current in coil is ​

Answer 1

Induced current in the coil is 0.32 A.

Explanation:

Given that,

The rate of change on magnetic field, $\dfrac{dB}{dt}=0.4\ T/s$

Side of square, x = 4 cm = 0.04 m

Area of the square, $A=x^2=(0.04)^2=0.0016\ m^2$

Resistance of the coil, $R=2\times 10^{-3}\ \Omega$

Due to the change in the magnetic field, an emf is induced in it and it is given by :

$\epsilon=\dfrac{d(BA)}{dt}$

$\epsilon=A\dfrac{d(B)}{dt}$  

$\epsilon=0.0016\times 0.4$  

$\epsilon=0.00064\ V$

Using Ohm's law :

$\epsilon=I\times R$

$I=\dfrac{\epsilon}{R}$

$I=\dfrac{0.00064}{2\times 10^{-3}}$

I = 0.32 A

So, the induced current in the coil is 0.32 A. Hence, this is the required solution.

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Topic : Induced EMF

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