Question

magnetic field changes at the rate of 0.4 T/sec.in a square coil of side 4 cm kept perpendicular to the field if the resistance of the coil is 2 ×10*-3 then induced current in coil is​

Answer 1

Answer:

induced current= 0.34

Explanation:

magnetic field dB= 0.4/s

area A= 4cm x 4cm = 16x10*-4 m^2

then emf= dB.Acos(0) = 0.4 x 16x10*-4 = 6.8x10*-4 V

resistance R= 2x10*-3

induced current = V/R =  (6.8x10*-4) /( 2x10*-3) = 0.34A