Magnetic field due to 0.1 A current flowing through a circular
coil of radius 0.Im and 1000 turns at the centre of the coil is
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We know that
B = m Ni/2r
B = 4pi × 10^-7 ×1000 ×0.1/2×0.1
B = 2 pi × 10^-4
Put value of pi
B = 2×3.14×10^-4
B = 6.28×10^-4
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