Physics, asked by sarthak6619, 7 months ago

Magnetic field due to a bar magnet 2cm long having a pole strength of 100 Am at a point 10 cm

from each pole isl

a) 2 x 10-4 T b) 8 x 10-4T c) 2 x 10-5 T d) 4 x 10-4 T​

Answers

Answered by debisinghmajhi8
5

*Answer*is the ( c ) I am just trying to the answer

Answered by archanajhaa
0

Answer:

The magnetic field due to a bar magnet is 2×10⁻⁴T i.e.option(a).

Explanation:

As the point is 10 cm from each pole that means it is at its equatorial position.

The magnetic field at a point on the equatorial line of a bar magnet is given by,

B_e_q_u_a_t_o_r_i_a_l=\frac{\mu_0 M}{4\pi r^3}        (1)

Where,

μ₀=4π×10⁻⁷

M=magnetic moment

r=distance of the point from the bar magnet

According to the question,

M=m×2l=100×2×10⁻²=2

r=10× 10⁻²

By putting the values in equation (1) we get;

B_e_q_u_a_t_o_r_i_a_l=\frac{4\pi \times 10^-^7\times 2}{4\pi (0.1)^3}=2\times 10^-^4T

Hence, the magnetic field due to a bar magnet 2cm long having a pole strength of 100 Am at a point of 10 cm from each pole is 2×10⁻⁴T i.e.option(a).

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