Question

Magnetic field due to given circular Loop as its centre given that resistance is 10ohm radius is 4m

Answer 1

Answer:

Resistance ABC=5Ω, Resistance ADC=10Ω

Current ABC=

3

2

I, Current ADC=

3

1

I

Magnetic field due to ABC

B

1

=

4R

μ

0

I

ABC

out of plane.

=

6R

μ

0

I

Similarly, B

2

=

4R

μ

0

I

ADC

=

12R

μ

0

I

⟹B

net

(B

1

−B

2

)=

12R

μ

0

I

solution