Question

Magnetic field linked through a coil of 50Ω resistance varying with time as shown in graph. (given time in sec and flux in weber)

♣Draw the graph of
1)emf-time
2) Current-time

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Answer 1

Answer:

Required graphs are in the attachment.

Explanation:

1. Emf - time graph :

We know that,

$\boxed{\mathrm{Emf\ (\epsilon) = \dfrac{d\phi}{dt}}}$

Here, Ф = Magnetic flux

So, Slope of magnetic flux - time graph gives us the EMF

• From seconds 0 to 2, Slope = 25/2 = 12.5
• From seconds 2 to 4, Slope = 0 as it is a horizontal line
• From seconds 4 to 6,

         $\mathrm{Slope = \dfrac{-20-25}{6-4} = \dfrac{-45}{2} = -22.5}$

2. Current-time graph :

we know that,

$\boxed{\mathrm{I = \dfrac{EMF(\epsilon)}{Resistance(R)}}}$

Here, R = 50 Ω

As,  ${\mathrm{I = \dfrac{\epsilon}{R}}}$

$\implies {\mathrm{I = \dfrac{d\phi}{dt. R}}}$

$\boxed{\mathrm{I = \dfrac{d\phi}{dt (50)}}}$

So, Slope of flux time graph per resistance gives us current

• From seconds 0 to 2, I = 12.5/50 = 1/4 = 0.25
• From seconds 2 to 4, I = 0/50 = 0
• From seconds 4 to 6, I = -22.5/50 = -0.45

Hope it helps!!