Question

Magnetic field strength at the center of
the circular coil of radius r carrying
mol
currentiis B=2r N (where
Но Permeability of vacuum (a
constant)
B = Magnitude of magnetic field
strength at the center of the circular
coil
i = Current in coil
r = Radius of coil
N = Number of truns in the coil)
Then consider a wire in the form of a
circular loop of one turn carrying a
current produces a magnetic field
strength B at the centre. If the same
wire is looped into a coil of two turns
and carries the same current, the new
value of magnetic induction at the
centre is
2 x B. Find the value of x.​

Answer 1

Answer:

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