Question

Magnetic flux associated with a coil of 200 turns decreases to 0.5 Wb from 1 Wb
within 0.1 second. Find out the induced e.m.f between the ends of the coil due to the
above change​

Answer 1

Answer:

According to Faraday's law , the induced emf in a coil (having N turns) is the rate of change of magnetic flux linked with coil ,

               e=NdtdϕB

given -     ϕB=(t2−2t)×10−3

or            dtdϕB=(2t−2)×10−3

Therefore , induced emf in coil , having turns N=200 , 

               e=200(2t−2)×10−3

at t=3s 

   e=200(2×3−2)×10−3=0.8V

your answer=0.8V