Question

Magnetic flux in a circuit containing a coil of resistance 2Ω changes from 2.0 Wb to 10 Wb in 0.2 sec. The charge passed through the coil in this time is
(a) 0.8 C(b) 1.0 C(c) 5.0 C(d) 4.0 C

Answer 1

answer : option (d) 4C

explanation : use formula, $\Delta Q=\frac{\Delta \phi}{R}$

where ∆Q is charge passed through the coil in given time , $\Delta\phi$ is change in magnetic flux through coil and R is the resistance of coil

here, initial magnetic flux = 2Wb

final magnetic flux = 10Wb

so, change in magnetic flux = 8Wb

resistance of coil = 2 ohm

so, ∆Q = 8/2 = 4C

hence, option (d) is correct.