Physics, asked by fouzan1896, 1 year ago

Magnetic flux in a circuit containing a coil of resistance 2ohm changes from 2 wb to10wb in 0.2 sec the charge passed through the coil in this time is

Answers

Answered by bharatdeepracepax6f3
52
induced emf in coil (E) = change in Φₘ / t
= (10 - 2) / 0.2
= 40

now , E = I . r
I = 40 / 2
I = 20 Amp
I.t = q
=> q = 20 x 0.2 = 4 C
Answered by gadakhsanket
7

Dear Student,

◆ Answer -

Q = 4 C

● Explanation -

# Given -

Φ1 = 2 Wb

Φ2 = 10 Wb

R = 2 ohm

t = 0.2 s

# Solution -

EMF induced in the coil is -

V = ∆Φ/dt

V = (Φ2-Φ1)/dt

V = (10-2)/0.2

V = 40 V

Charge passed through the coil is -

Q = I.t

Q = (V/R).t

Q = (40/2) × 0.2

Q = 4 C

Hence, charge passed through the coil is 4 C.

Thanks dear. Hope this helps you...

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