CBSE BOARD XII, asked by Ananyasingh8405, 10 months ago

Magnetic flux of 50 uwb is linked with a coil .when current of 0.1 MA flows through it.what is self inductance of coil.

Answers

Answered by NitinPetash
6

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Answered by handgunmaine
3

The self inductance of coil is 500 Henry.

Explanation:

Given that,

Magnetic flux of the coil, \phi=50\ \mu Wb=50\times 10^{-6}\ Wb

Current, I=0.1\ MA=0.1\times 10^{-6}\ A

To find,

The self inductance of the coil.

Solution,

The self inductance of the coil is given by :

L=\dfrac{\phi}{I}

L=\dfrac{50\times 10^{-6}}{0.1\times 10^{-6}}

L = 500 Henry

So, the self inductance of coil is 500 Henry. Hence, this is the required solution.

Learn more,

Self inductance

https://brainly.in/question/2754193

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