Question

Magnetic moment of a 3d  series element ‘A’ is 4.92 BM if magnetic moment of  is also 4.92BM then what is the group number of A in modern periodic table (according to IUPAC convention)​

Answer 1

answer is 42....................

Answer 2

Answer:

Element A has 8 group number in the modern periodic table.

Explanation:

• Magnetic moment of  element A, μ = 4.92BM. It is only possible if the element have four unpaired electrons in its valence shell.
• If n=4 then, magnetic moment $\sqrt{n(n+2)} =\sqrt{4(4+2} = 4.9BM$ .
• In  3d series the electronic configuration of Fe= [Ar] 3d⁶4s². It has four unpaired electrons in its valence shell. Iron belongs to group 8.

Therefore element A is iron, which belongs to group eight in the modern periodic table.