Question

Magnetic moment of a cobalt compound is 4.899 B.M. Write the electronic configuration of the metal ion present in the compound.

Answer 1

Answer:

contains 3d

7

CO +2 electrons in the outermost orbit. As it is showing the square planar geometry, the electronic configuration will be d

xz

2

, d

yz

2

, d

z

2

2

, d

xy

1

. Hence the number of unpaired electrons (n) will be 1. By substituting this value in the formula of magnetic moment μ=

n(n+2)

. μ will be 1.73 B.M.