Question

Magnetic moment of compound of Vanadium is 1.73BM. Calculate in which oxidation state Vanadium is present in that compound?​

Answer 1

Answer:The ‘value of x’ is 4.

Solution:

The number of unpaired electrons can be found from the magnetic moment using the below relation,

Here, n is the number of unpaired electrons in an element.

So,

Squaring on both sides of equation (1), we get

The quadratic equation (3) is solved as follows

So the positive value of n will be 1.

Thus, it is found that the number of unpaired electrons in the vanadium with magnetic moment of 1.73 BM should be 1.

The electronic configuration of Vanadium shows that the last shells has configuration of .

So in order to have one unpaired electrons in this element, four electrons should be given away that means the oxidation state of Vanadium will be in +4 state.

Explanation: