Question

magnetic moment of cr 3+

Answer 1

The spin only magnetic moment of Cr³⁺ is 3.87 BM.

Given-

• Atomic number of Cr = 24

Electronic configuration of Cr³⁺ = [Ar] 3d³

From the electronic configuration it is clear that number of unpaired electrons is 3 which is present in d orbital.

So the spin only magnetic moment is = √n(n+2)

μ = √n(n+2)

By substituting the values we get

μ = √3(3+2) = √15 = 3.87 BM

Answer 2

Here we have to find the magnetic moment of Cr³⁺

We will first have to write the electronic configuration of  Cr³⁺

Electronic configuration: 1s²2s²2p⁶3s²3p⁶3d³

Now, there are 3 unpaired electrons

The formula to calculate magnetic moment is

magnetic moment = $\sqrt{n(n+2)}$

Where n = number of unpaired electrons

On putting the value of n=3

The magnetic moment comes out to be 3.87