Magnetic moment of KO2.how to find it?
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Pottasium in KO2 has Oxidation state is +1
EC of K :1s2 2s2 2p6 3s2 3p6 4s1
So if it loses one electrone
then EC :1s2 2s2 2p6 3s2 3p6 which has 0 unpaired electrons
MM=✓n(n+2)=0
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