Question

Magnetic Moment of X3+ ion of 3d series is√35 BM . What is the atomic number of X3+ ?



Magnetic moment =√(n(n+2) where n is no of unpaired electron

Answer 1

Answer: Atomic number of $X^{3+}$ is 23.

Explanation:

The oxidation state of X is, 3

The number of unpaired electrons in X = ?

Formula used for magnetic moment :

$\mu=\sqrt{n(n+2)}$

where,

$\mu$ = magnetic moment

n = number of unpaired electrons

Now put all the given values in the above formula, we get the magnetic moment.

$\sqrt{35}=\sqrt{n(n+2)}$

$n=5$

Thus the element in +3 oxidation state contained 5 unpaired electrons and belong to 3d series.

Thus the element had lost 2 electrons from 4s shell and  1 electron from 3d shell.

Th electronic configuration of X is,

$1s^22s^22p^63s^23p^63d^64s^2$

The atomic number of X is 26.

Th electronic configuration of $X^{3+}$ is,

$1s^22s^22p^63s^23p^63d^5$

Atomic number of $X^{3+}$ is 23.

Answer 2

Explanation:

The oxidation state of X is, 3

The number of unpaired electrons in X = ?

Formula used for magnetic moment :

\mu=\sqrt{n(n+2)}μ=

n(n+2)

where,

\muμ = magnetic moment

n = number of unpaired electrons

Now put all the given values in the above formula, we get the magnetic moment.

\sqrt{35}=\sqrt{n(n+2)}

35

=

n(n+2)

n=5n=5

Thus the element in +3 oxidation state contained 5 unpaired electrons and belong to 3d series.

Thus the element had lost 2 electrons from 4s shell and 1 electron from 3d shell.

Th electronic configuration of X is,

1s^22s^22p^63s^23p^63d^64s^21s

2

2s

2

2p

6

3s

2

3p

6

3d

6

4s

2

The atomic number of X is 26.

Th electronic configuration of X^{3+}X

3+

is,

1s^22s^22p^63s^23p^63d^51s

2

2s

2

2p

6

3s

2

3p

6

3d

5

Atomic number of X^{3+}X

3+

is 23.