magnetic momentum of Sc+1
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The spin magnetic moment is calculated by given below formula : where n is number of unpaired electron. So, number of unpaired electron in Sc+3 is....
Magnetic moment is calculated by the formula
μ = √n(n+2) B.M
find the no. of unpaired electrons.
Atomic no. Of Sc is 21.
So, the electron configuration will be
[Ar] 4s^2 3d^1
Since it’s given Sc^+1
One electron will be removed from the outermost orbit as
[Ar] 4s^1 3d^1
Here we can see,
There are 2 unpaired electrons.
So,
μ = √2(2+2)
μ = √8 B.M
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Magnetic moment is calculated by the formula
μ = √n(n+2) B.M
Where,
μ is the Magnetic Moment.
n is the no. of unpaired electrons.
B.M. = Bohr Magneton ( unit of magnetic moment)
First find the no. of unpaired electrons.
Atomic no. Of Sc is 21.
So, the electron configuration will be
[Ar] 4s^2 3d^1
Since it’s given Sc^+1
One electron will be removed from the outermost orbit as
[Ar] 4s^1 3d^1
Here we can see,
There are 2 unpaired electrons.
So,
μ = √2(2+2)
μ = √8 B.M
μ = √n(n+2) B.M
Where,
μ is the Magnetic Moment.
n is the no. of unpaired electrons.
B.M. = Bohr Magneton ( unit of magnetic moment)
First find the no. of unpaired electrons.
Atomic no. Of Sc is 21.
So, the electron configuration will be
[Ar] 4s^2 3d^1
Since it’s given Sc^+1
One electron will be removed from the outermost orbit as
[Ar] 4s^1 3d^1
Here we can see,
There are 2 unpaired electrons.
So,
μ = √2(2+2)
μ = √8 B.M
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