Chemistry, asked by jashanpreetkaur346, 10 months ago

Magnetic quantum number of 29th electron of copper is

Answers

Answered by nishantsingh34
3

Answer:

The magnetic quantum number of 29th electron of copper is (a) +1 (b) –3 (c) –1 (d) –2

Top answer · 1 vote

Correct option (c) –1 Explanation: Valence shell electronic configuration of Cu is Here m for 29th electron is –1 More

Answered by OlaMacgregor
2

Magnetic quantum number of 29th electron of copper is -3 to +3.

Explanation:

We calculate the azimutal numbers as follows.

                      n = l + 1

where,     n = principle quantum number  

                l = azimuthal quantum number

Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l can be 0, 1, 2, 3, and so on.

Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.  

So, when n = 1 then l = 0 and m = 0.

For example, for 29th electron of copper the electron distribution will be as 2, 8, 18, 1. This means that n = 4 for 29th electron of copper.

Hence, value of l will be calculated as follows.

                 n = l + 1

                 4 = l + 1

                  l = 3

So, m will be from -3 to +3.

Learn more about quantum numbers:

https://brainly.com/question/2193783

https://brainly.com/question/14782569

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