Question

Magnification,
1.15 m
-5.00 m
The image is virtual, erect and smaller in sine by a factor of 0.23
Example 10.2
An object, 4.0 cm in sice, is placed at 25.0 cm in front of a concave
mirror of focal length 15.0 cm. At what distance from the mirror
should a screen be placed in order to obtain a sharp image? Find
the nature and the size of the image
Solution
Object-size, h = +4.0 cm;
Object-distance, u=- 25.0 cm;
Focal length, J = -15.0 cm;
Image distance, V = ?
Image-size, h'?
From Eq. (10.1);
1 1
1​

Answer 1

Answer:

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