Question

magnification of a mirror is -1. what type of mirror is it ? what is the position of object and image? give the nature of image

Answer 1

Answer:

concave, position of object and image are the same (i.e. at C), image is real and inverted

Explanation:

concave mirror has negative magnification in all cases (exc. when object is between F and O.

ATQ size of object = size of image

this happens in 1 case (i.e when object is at C)

magnification = -v/u

therefore v=u            [object and image have same position]

since the magnification is negative, image is formed below principal axis. hence it real and inverted.

Answer 2

Answer:

Magnification=I/O

=> ( -3)=(-v)/u

=> (-3) *u = v

=> v= 3u

Explanation:

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