magnification of object is +3 what will be the position of image
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Answered by
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let the image formed is virtual the M=uv
then v=3u. and let u=d
applying lens formula f1=3d1−d1
f=−23d now as position of object and lens is changed then direction of travelling of light also changes then both f and u changes their sign.
now again applying lens formula we get 3d2=v1−−d1
then v=3d
and M=uv=3.
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