Physics, asked by minakshimishra44, 10 months ago

Magnification produced by a concave mirror for an object of height 10cm is 0.25 find the height of image and mention whether it is erect or inverted.t

Answers

Answered by omsamarth4315
0

Answer:

height is 0.25 × 10

= 2.5 cm.

it is erect.

Answered by kartavyaguptasl
0

Answer:

The height of the image is found to be 40 cm and it is an erect image.

Explanation:

Erect and inverted Images:

In optics, an upright (erect) image is an image that is displayed in the correct orientation. The image is formed when rays from a point on the original object meet again after passing through the optical system. In an upright image,  in contrast to an inverted image, the orientation is the same as the object.

An inverted (flipped) image means that the image is upside down compared to the object. The real image formed by the curved mirror is inverted. Rays from the top edge of the object are reflected downward by the concave mirror below the main axis. Similarly, the rays are reflected upwards from the bottom edge of the mirror.

Magnification:

Physically, we all understand what the magnification is. This can be defined as how large or small the image looks compared to the size of the object.

This is expressed as the ratio of the height of the image to the ratio of the height of the object. The magnification is indicated by the letter "m". Where, Magnification (m) = h / h'

Also, h' is the height of the image and h is the height of the object.

Now, substituting the values, we get:

0.25=\frac{10}{h}

simplifying which, we get:

h = 40 cm.

As height is positive, so it is erect.

#SPJ2

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