Question

Magnify the triangle with vertices a(0,0), b(1,1) and c(5,2) to twice its size while keepingc(5,2) fixed.

Answer 1

Answer:

ΔCDE = C(5,2) , D (-5 , -2) , E  (-3 ,0)

Step-by-step explanation:

Magnify the triangle with vertices a(0,0), b(1,1) and c(5,2) to twice its size while keepingc(5,2) fixed.

Current triangle is Δ CAB

we will make Δ CDE

Δ CAB ≅ Δ CDE

CA/CD = CB/CE = AB/DE = 1/2

CD = 2CA

=> A will be midpoint of CD

(0 , 0) = (Dₓ + 5)/2  , (Dy + 2)/2

=> Dₓ = -5   Dy = -2

D (-5 , -2)

Similarly CE = 2CB

=> B will be midpoint of CE

(1 , 1) = (Eₓ + 5)/2  , (Ey + 2)/2

Eₓ = -3   Ey = 0

E = (-3 ,0)

ΔCDE = C(5,2) , D (-5 , -2) , E  (-3 ,0)

Verification

CA = √29

CB = √17

AB = √2

CD = √116 = 2√29 = 2CA

CE = √68 = 2√17 = 2CB

DE = √8 = 2√2 = 2AB