Question

magnitude of 2i +yj+3k=5 then y=

Answer 1

Answer:

y=√12

Explanation:

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Answer 2

Answer:

y= 2√3

Explanation:

Concept- The magnitude in 2- dimensions is written as;

$\sqrt{ {x}^{2} + {y}^{2} }$

The magnitude of 3 - dimensions can be written as ;

$\sqrt{ { x}^{2} + {y}^{2} + {z}^{2} }$

Calculation:

Now in our question we have

2i+yj+3k=5 ...(1)

Squaring equation (1) we get;

$4 + {y}^{2} + 9 = 25$

${y}^{2} = 25 - 13$

${y}^{2} = 12$

$y = \sqrt{12}$

$y = 2 \sqrt{3}$

Result:

y= 2√3