Magnitude of a physical quantity is independent -------------
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This implies that the components of the vector with respect with the basis {x, y, z} simply represent how the numerical value of the force as we measure it is distributed among the three different directions that we observe, but the magnitude, which is independent of direction, is what we measure the force itself to be ...
Magnitude is a property of a specific type of quantity, called a geometric vector quantity. If this geometric vector is furthermore a physical quantity, then the interpretation I would suggest for the magnitude of this physical quantity is the interpretation of distribution. Let me explain. For an example, suppose we have a force F = (Ax + By + Cy) in Newtons. This vector has a magnitude of Sq-rt(A^2 + B^2 + C^2), and a direction of u = (Ax + By + Cy)/Sq-rt(A^2 + B^2 + C^2). Thus, F = Sq-rt(A^2 + B^2 + C^2) u. Now I’ve written the vector in terms of its two essential vector properties. Now, I could change the values of A, B, & C interdependently, such that u remains a unit vector, and regardless of what this arbitrary unit vector is, the magnitude will remain the same. This implies that the components of the vector with respect with the basis {x, y, z} simply represent how the numerical value of the force as we measure it is distributed among the three different directions that we observe, but the magnitude, which is independent of direction, is what we measure the force itself to be as a number with meaning.
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Magnitude is a property of a specific type of quantity, called a geometric vector quantity. If this geometric vector is furthermore a physical quantity, then the interpretation I would suggest for the magnitude of this physical quantity is the interpretation of distribution. Let me explain. For an example, suppose we have a force F = (Ax + By + Cy) in Newtons. This vector has a magnitude of Sq-rt(A^2 + B^2 + C^2), and a direction of u = (Ax + By + Cy)/Sq-rt(A^2 + B^2 + C^2). Thus, F = Sq-rt(A^2 + B^2 + C^2) u. Now I’ve written the vector in terms of its two essential vector properties. Now, I could change the values of A, B, & C interdependently, such that u remains a unit vector, and regardless of what this arbitrary unit vector is, the magnitude will remain the same. This implies that the components of the vector with respect with the basis {x, y, z} simply represent how the numerical value of the force as we measure it is distributed among the three different directions that we observe, but the magnitude, which is independent of direction, is what we measure the force itself to be as a number with meaning.
......please mark it as the brainliest if you are satisfied...♥️♥️♥️
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Magnitude of the physical quantity is independent of dash
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