Physics, asked by shaisthafasi31, 1 month ago

Magnitude of electric field due to an electric dipole at a distance r from it, at axial position is given as E. The magnitude of electric field due to the dipole at a distance 2r from it, on equatorial line is
1.E/8
2.E/16
3.8E
4.16E

Answers

Answered by TharanNath
16

Answer:

E/16

Have a gud day!

Answered by DiyaTsl
0

Answer:

The magnitude of electric field is   \frac{E}{16}  . So, option 2 is its answer.

Explanation:

  • Magnitude of electric field due to an electric dipole at a distance r from it at axial position is given by E.

       we know that Electric field at axial position =  \frac{2KP}{r^{3} }

    According to question,

                     E  =   \frac{2KP}{r^{3} }

  • Magnitude of electric field due to an electric dipole at as distance r from it at equatorial position is given by,

                 E ' = \frac{KP}{r^{3} }

  • The magnitude of electric field due to the dipole at a distance 2rfrom it, on equatorial line is given by ,

                           E' =  \frac{2KP}{(2r)^{3} }

                         E'  =     \frac{KP}{8r^{3} }

  •  Multiply both numerator and denominator by 2 on RHS.

       E' =   \frac{2KP}{16r^{3} }

         E'  =  \frac{E}{16}                             where , E  =    \frac{2KP }{r^{3} }

Thus, the magnitude of electric field due to the dipole at a distance 2r from it, on equatorial line is      \frac{E}{16}.

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