Question

Magnitude of electric field due to an electric dipole at a distance r from it, at axial position is given as E. The magnitude of electric field due to the dipole at a distance 2r from it, on equatorial line is
1.E/8
2.E/16
3.8E
4.16E

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Answer 1

Answer:

E/16

Have a gud day!

Answer 2

Answer:

The magnitude of electric field is   $\frac{E}{16}$  . So, option 2 is its answer.

Explanation:

• Magnitude of electric field due to an electric dipole at a distance r from it at axial position is given by E.

       we know that Electric field at axial position =  $\frac{2KP}{r^{3} }$

    According to question,

                     $E$  $=$   $\frac{2KP}{r^{3} }$

• Magnitude of electric field due to an electric dipole at as distance r from it at equatorial position is given by,

                 $E ' = \frac{KP}{r^{3} }$

• The magnitude of electric field due to the dipole at a distance $2r$from it, on equatorial line is given by ,

                           $E' = \frac{2KP}{(2r)^{3} }$

                         $E' = \frac{KP}{8r^{3} }$

•  Multiply both numerator and denominator by $2$ on RHS.

       $E' = \frac{2KP}{16r^{3} }$

         $E' = \frac{E}{16}$                             where , $E = \frac{2KP }{r^{3} }$

Thus, the magnitude of electric field due to the dipole at a distance 2r from it, on equatorial line is      $\frac{E}{16}$.

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