Question

Magnitude of force experience by an object moving with speed v is given by F=kv^2 Find the dimension of k

Answer 1

F=kv2

K=F/v2

F=(MLT^-2)

V=(LT^-1)

K=(MLT^-2)/(L^2T^-2)

K=ML^-1T^0

Answer 2

Answer:

F=Kv^2

Taking dimensions of each term, we get

[MLT^−2]=[K][LT^−1]^2

⇒[K]=[MLT^−2][L^2T^−2]

[K]=[ML^−1]

Explanation: