Magnitude of resultant of two forces is equal to the magnitude of their difference. What is the angle between the two?
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Assuming the forces have a magnitude of 1 unit:
Rotate the plane such that Force 1 is pointing towards the positive x axis and the plane two forces lie on is the x-y plane.
Now let θ be the angle between Force 1 and Force 2.
Then, we can resolve these to 3 forces:
Fx1=1
Fx2=1×cosθ=cosθ
Fy2=1×sinθ=sinθ
Therefore, the magnitude of the resultant force will be
(Fx1+Fx2)2+F2y2−−−−−−−−−−−−−−−√
=(1+cosθ)2+sin2θ−−−−−−−−−−−−−−−√
=1
(1+cosθ)2+sin2θ=1=sin2θ+cos2θ
(1+cosθ)2=cos2θ
1+2cosθ+cos2θ=cos2θ
cosθ=−12
∴θ=120°=2π3rad
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Hope this help...........
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