Physics, asked by marniebarkataki, 8 months ago

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1. A body of mass 500 g, initially at rest, is acted upon
by a force which causes it to move a distance of 4
m in 2 s. Calculate the force applied.​

Answers

Answered by Anonymous
6

\color{darkblue}\underline{\underline{\sf Given-}}

  • Mass of body (m) = 500g or 0.5kg
  • Initially body is at rest (u) = 0
  • When force is applied it moves by distance (s) = 4m in time (t) =2s

\color{darkblue}\underline{\underline{\sf To \: Find-}}

  • Force applied ( F )

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Velocity

\color{violet}\bullet\underline{\boxed{\sf Velocity=\dfrac{s}{t}}}

v = finial Velocity of body

s = distance

t = time

\implies{\sf v =\dfrac{4}{2}}

\color{orange}\implies{\sf v = 2m/s}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Acceleration

From Newton's First Law Of Motion

\color{violet}\bullet\underline{\boxed{\sf v=u+at}}

v = final velocity of body

u = Initial velocity of body

a = acceleration

t = time

\implies{\sf 2=0+a×2 }

\color{orange}\implies{\sf a=1\:m/s^2}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

From Newton's Second Law

\Large\color{violet}\bullet\underline{\boxed{\sf F=ma}}

F = force applied

m = mass of body

a = acceleration

\implies{\sf F=0.5×1 }

\color{red}\implies{\sf F=0.5N}

\color{darkblue}\underline{\underline{\sf Answer-}}

Force applied to the body is \color{red}{\sf 0.5N}

Answered by ShivamKashyap08
16

Answer:

  • The Force (F) Applied on the body is 1 N.

Given:

  1. Mass of the body (M) = 500 g = 0.5 Kg
  2. Distance covered (S) = 4 m
  3. Time taken (t) = 2 sec.
  4. Initial velocity (u) = 0 m/s.

Explanation:

\rule{300}{1.5}

From second Kinematic equation we know,

S = u t + 1 / 2 a t²

Where,

  • S Denotes Distance travelled.
  • u Denotes Initial velocity.
  • t Denotes Time taken.
  • a Denotes Acceleration.

Now,

⇒ S = u t + 1 / 2 a t²

Substituting the values,

⇒ 4 = 0 × 2 + 1 / 2 × a × (2)²

⇒ 4 = 0 + 1 / 2 × a × 4

⇒ 4 = 1 / 2 × a × 4

⇒ 4 = a × 2

⇒ a = 4 / 2

⇒ a = 2

a = 2 m/s²

We got the acceleration.

\rule{300}{1.5}

\rule{300}{1.5}

From Newton's Second law

F = M a

Where,

  • F Denotes Force.
  • M Denotes Mass.
  • a Denotes acceleration.

Now,

⇒ F = M a

Substituting the values,

⇒ F = 0.5 Kg × 2 m/s²

⇒ F = 0.5 × 0.2

⇒ F = 1

F = 1 N.

The Force (F) Applied on the body is 1 N.

\rule{300}{1.5}

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